Solution:
Let the common ratio between the angles be $x$. Therefore, the angles will be $3 x, 5 x, 9 x$, and $13 x$ respectively.
As the sum of all interior angles of a quadrilateral is $360^{\circ}$,
$\therefore 3 x+5 x+9 x+13 x=360^{\circ}$
$30 x=360^{\circ}$
$x=12^{\circ}$
Hence, the angles are
$3 x=3 \times 12=36^{\circ}$
$5 x=5 \times 12=60^{\circ}$
$9 x=9 \times 12=108^{\circ}$
$13 x=13 \times 12=156^{\circ}$
Let the common ratio between the angles be $x$. Therefore, the angles will be $3 x, 5 x, 9 x$, and $13 x$ respectively.
As the sum of all interior angles of a quadrilateral is $360^{\circ}$,
$\therefore 3 x+5 x+9 x+13 x=360^{\circ}$
$30 x=360^{\circ}$
$x=12^{\circ}$
Hence, the angles are
$3 x=3 \times 12=36^{\circ}$
$5 x=5 \times 12=60^{\circ}$
$9 x=9 \times 12=108^{\circ}$
$13 x=13 \times 12=156^{\circ}$
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