Question:
The area of a sector of a circle of radius $2 \mathrm{~cm}$ is $\pi \mathrm{cm}^{2}$. Find the angle contained by the sector.
Solution:
We know that the area A of a sector of an angle θ in the circle of radius r is given by
$A=\frac{\theta}{360^{\circ}} \times \pi r^{2}$
It is given that $r=2 \mathrm{~cm}$ and area $A=\pi \mathrm{cm}^{2}$.
Now we substitute the value of r and A in above formula to find the value of θ,
$\pi=\frac{\theta}{360^{\circ}} \times \pi \times 2 \times 2$
$\theta=\frac{360^{\circ} \times \pi}{\pi \times 2 \times 2}$
$=90^{\circ}$
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