The area of ∆ABC with vertices A(3, 0), B(7, 0) and C(8, 4) is


The area of ∆ABC with vertices A(3, 0), B(7, 0) and C(8, 4) is

(a) 14 sq units
(b) 28 sq units
(c) 8 sq units
(d) 6 sq units


(c) 8 sq units

The given points are $A(3,0), B(7,0)$ and $C(8,4)$.

Here, $\left(x_{1}=3, y_{1}=0\right),\left(x_{2}=7, y_{2}=0\right)$ and $\left(x_{3}=8, y_{3}=4\right)$


Area of $\Delta A B C=\frac{1}{2}\left[x_{1}\left(y_{2}-y_{3}\right)+x_{2}\left(y_{3}-y_{1}\right)+x_{3}\left(y_{1}-y_{2}\right)\right]$



$=\left(\frac{1}{2} \times 16\right)$

$=8$ sq units


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