Question:
The capacity of a cylindrical vessel with a hemispherical portion raised upward at the bottom as shown in the figure is $\frac{\pi r^{2}}{3}[3 h-2 r]$.
Solution:
True
We know that, capacity of cylindrical vessel = πr2h cm3
and capacity of hemisphere $=\frac{2}{3} \pi r^{3} \mathrm{~cm}$
From the figure, capacity of the cylindrical vessel
$=\pi r^{2} h-\frac{2}{3} \pi r^{3}=\frac{1}{3} \pi r^{2}[3 h-2 r]$
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.