**Question:**

The congruent circles with centres O and O’ intersect at two points A and B. Then, ∠AOB = ∠AO’B.

**Solution:**

True

Join AB, OA and OB, O’A and BO’.

In ΔAOB and ΔAO’B,

OA = AO’ [both circles have same radius]

OB = BO’ [both circles have same radius]

and AB= AB [common chord]

ΔAOB = ΔAO’B [by SSC congruence rule]

=> ∠AOB = ∠AO’B [by CPCT]