The correct order for acid strength of compounds

Question:

The correct order for acid strength of compounds $\mathrm{CH} \equiv \mathrm{CH}$,

$\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{CH}$ and $\mathrm{CH}_{2}=\mathrm{CH}_{2}$ is as follows:

  1. $\mathrm{CH} \equiv \mathrm{CH}>\mathrm{CH}_{2}=\mathrm{CH}_{2}>\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{CH}$

  2. $\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{CH}>\mathrm{CH} \equiv \mathrm{CH}>\mathrm{CH}_{2}=\mathrm{CH}_{2}$

  3. $\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{CH}>\mathrm{CH}_{2}=\mathrm{CH}_{2}>\mathrm{HC} \equiv \mathrm{CH}$

  4. $\mathrm{HC} \equiv \mathrm{CH}>\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{CH}>\mathrm{CH}_{2}=\mathrm{CH}_{2}$

Correct Option: , 4

Solution:

Leave a comment

Close

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now

eSaral Gurukul

NEET

JEE Main

JEE Advanced

Our Telegram Channel

All Study Material