The correct order of the ionic radii of

Question:

The correct order of the ionic radii of $\mathrm{O}^{2-}, \mathrm{N}^{3-}, \mathrm{F}^{-}, \mathrm{Mg}^{2+}$, $\mathrm{Na}^{+}$and $\mathrm{Al}^{3+}$ is :

  1. $\mathrm{N}^{3-}<\mathrm{O}^{2-}<\mathrm{F}^{-}<\mathrm{Na}^{+}<\mathrm{Mg}^{2+}<\mathrm{Al}^{3+}$

  2. $\mathrm{Al}^{3+}<\mathrm{Na}^{+}<\mathrm{Mg}^{2+}<\mathrm{O}^{2-}<\mathrm{F}^{-}<\mathrm{N}^{3-}$

  3. $\mathrm{Al}^{3+}<\mathrm{Mg}^{2+}<\mathrm{Na}^{+}<\mathrm{F}^{-}<\mathrm{O}^{2-}<\mathrm{N}^{3-}$

  4. $\mathrm{N}^{3-}<\mathrm{F}^{-}<\mathrm{O}^{2-}<\mathrm{Mg}^{2+}<\mathrm{Na}^{+}<\mathrm{Al}^{3+}$

Correct Option: , 3

Solution:

All are isoelectronic species, so more is the $Z_{\text {eff }}$ less will be the ionic size.

$\therefore$ Correct order of ionic radii is

$\mathrm{Al}^{3+}<\mathrm{Mg}^{2+}<\mathrm{Na}^{+}<\mathrm{F}^{-}<\mathrm{O}^{2-}<\mathrm{N}^{3-}$

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