The decimal expansion of


The decimal expansion of $\frac{147}{120}$ will terminate after how many places of decimal?

(a) 1

(b) 2

(c) 3

(d) will not terminate


The given number is $\frac{147}{120}$. We have to change the denominator in the form of $2^{m} \times 5^{n}$ and the given number terminates after largest of $m$ and $n$.

$\frac{147}{120}=\frac{147}{2^{3} \times 5 \times 3}$

$=\frac{49}{2^{3} \times 5^{1}}$

Here, $m=3, n=1$

Hence the given number terminates after 3 places.

Hence the correct option is $(c)$

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