The distance between the points (a cos 25°, 0) and (0, a cos 65°) is


The distance between the points (a cos 25°, 0) and (0, a cos 65°) is

(a) a

(b) 2a

(c) 3a

(d) None of these


We have to find the distance between $\mathrm{A}\left(a \cos 25^{\circ}, 0\right)$ and $\mathrm{B}\left(0, a \cos 65^{\circ}\right)$.

In general, the distance between $\mathrm{A}\left(x_{1}, y_{1}\right)$ and $\mathrm{B}\left(x_{2}, y_{2}\right)$ is given by,



$A B=\sqrt{\left(0-a \cos 25^{\circ}\right)^{2}+\left(a \cos 65^{\circ}-0\right)^{2}}$

$=\sqrt{\left(a \cos 25^{\circ}\right)^{2}+\left(a \cos 65^{\circ}\right)^{2}}$

$\cos 25^{\circ}=\sin 65^{\circ}$ and $\cos 65^{\circ}=\sin 25^{\circ}$

But according to the trigonometric identity,

$\sin ^{2} \theta+\cos ^{2} \theta=1$



So, the answer is (a)

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