The energy dissipated by a resistor

Question:

The energy dissipated by a resistor is $10 \mathrm{~mJ}$ in $1 \mathrm{~s}$ when an electric current of $2 \mathrm{~mA}$ flows through it. The resistance is________$\Omega$

(Round off to the Nearest Integer)

Solution:

$(2500)$

$\mathrm{Q}=\mathrm{i}^{2} \mathrm{RT}$

$\mathrm{R}=\frac{\mathrm{Q}}{\mathrm{i}^{2} \mathrm{t}}=\frac{10 \times 10^{-3}}{4 \times 10^{-6} \times 1}=2500 \Omega$

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