The figure formed by joining the midpoints of the adjacent sides of a rectangle of sides 8 cm and 6 cm is a

Question:

The figure formed by joining the midpoints of the adjacent sides of a rectangle of sides 8 cm and 6 cm is a

(a) rectangle of area $24 \mathrm{~cm}^{2}$

(b) square of area $24 \mathrm{~cm}^{2}$

(c) trapezium of area $24 \mathrm{~cm}^{2}$

(d) rhombus of area $24 \mathrm{~cm}^{2}$

 

Solution:

(d) rhombus of $24 \mathrm{~cm}^{2}$

We know that the figure formed by joining the midpoints of the adjacent sides of a rectangle is a rhombus.
So, PQRS is a rhombus and SQ and PR are its diagonals.
i.e., SQ = 8 cm and PR = 6 cm

$\therefore \operatorname{ar}($ rhombus $P Q R S)=\frac{1}{2} \times$ product of diagonals $=\frac{1}{2} \times 8 \times 6=24 \mathrm{~cm}^{2}$

 

Leave a comment

Close
faculty

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now