The foot of the perpendicular


The foot of the perpendicular drawn from the point $(4,2,3)$ to the line joining the points $(1,-2,3)$ and $(1,1,0)$ lies on the plane:

  1. (1) $2 x+y-z=1$

  2. (2) $x-y-2 z=1$

  3. (3) $x-2 y+z=1$

  4. (4) $x+2 y-z=1$

Correct Option: 1


Equation of line through points $(1,-2,3)$ and $(1,1,0)$ is

$\frac{x-1}{0}=\frac{y-1}{-3}=\frac{z-0}{3-0} \quad(=\lambda$ say $)$

$\therefore M(1,-\lambda+1, \lambda)$

Direction ratios of $\mathrm{PM}=[-3,-\lambda-1, \lambda-3]$

$\because P M \perp A B$

$\therefore(-3) \cdot 0+(-1-\lambda)(-1)+(\lambda-3) \cdot 1=0$

$\therefore \lambda=1$

$\therefore$ Foot of perpendicular $=(1,0,1)$

This point satisfy the plane $2 x+y-z=1$.

Leave a comment


Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now