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# The integral

Question:

The integral $\int \frac{d x}{(x+4)^{\frac{8}{7}}(x-3)^{\frac{6}{7}}}$ is equal to :

(where $\mathrm{C}$ is a constant of integration)

1. $\left(\frac{x-3}{x+4}\right)^{\frac{1}{7}}+C$

2. $-\left(\frac{x-3}{x+4}\right)^{\frac{1}{7}}+C$

3. $\frac{1}{2}\left(\frac{x-3}{x+4}\right)^{\frac{3}{7}}+C$

4. $-\frac{1}{13}\left(\frac{x-3}{x+4}\right)^{-\frac{13}{7}}+C$

Correct Option: 1

Solution: