The length of the minute hand of a clock is 14 cm.

Angle make by the minute hand in 1 minute = 6∘

Angle make by the minute hand in 5 minute = 5 ⨯ 6∘ = 30∘

Area of the sector having central angle is given by

$\frac{30^{\circ}}{360^{\circ}} \pi(14)^{2}$

$=\frac{1}{12} \times \frac{22}{7}(14)^{2}$

$=51.33 \mathrm{~cm}^{2}$

Hence, the area swept by minute hand in 5 minutes is 51.33 cm2