The locus of the midpoints of the chord of the circle,

Question:

The locus of the midpoints of the chord of the circle, $x^{2}+y^{2}=25$ which is tangent to the hyperbola, $\frac{x^{2}}{9}-\frac{y^{2}}{16}=1$ is :

  1. (1) $\left(x^{2}+y^{2}\right)^{2}-16 x^{2}+9 y^{2}=0$

  2. (2) $\left(x^{2}+y^{2}\right)^{2}-9 x^{2}+144 y^{2}=0$

  3. (3) $\left(x^{2}+y^{2}\right)^{2}-9 x^{2}-16 y^{2}=0$

  4. (4) $\left(x^{2}+y^{2}\right)^{2}-9 x^{2}+16 y^{2}=0$


Correct Option: , 4

Solution:

Equation of chord

$y-k=-\frac{h}{k}(x-h)$

$k y-k^{2}=-h x+h^{2}$

$h x+k y=h^{2}+k^{2}$

$y=-\frac{h x}{k}+\frac{h^{2}+k^{2}}{k}$

tangent to $\frac{x^{2}}{9}-\frac{y^{2}}{16}=1$

$c^{2}=a^{2} m^{2}-b^{2}$

$\left(\frac{h^{2}+k^{2}}{k}\right)^{2}=9\left(-\frac{h}{k}\right)^{2}-16$

$\left(x^{2}+y^{2}\right)^{2}=9 x^{2}-16 y^{2}$

 

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