Question:
The monkey B shown in figure holding on to the tail of the monkey A which is climbing up a rope. The masses of the monkeys $\mathrm{A}$ and $\mathrm{B}$ are $5 \mathrm{~kg}$ and $2 \mathrm{~kg}$ respectively. If A can tolerate a tension of $30 \mathrm{~N}$ in its tail, what force should it apply on the rope in order to carry the monkey B with it? Take $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}$.
Solution:
$T-5 g-30=5 a$ $30-2 g=2 a$
$\mathrm{T}=25+50+30=105 \mathrm{~N}=\mathrm{T}_{\max } \quad \mathrm{a}=5 \mathrm{~m} / \mathrm{s}^{2}$
