The monthly incomes of Aryan and Babban are in the ratio 3 : 4 and their monthly expenditures are in the ratio 5 : 7.

Solution:

Let the monthly incomes of Aryan and Babban be 3x and 4x, respectively.

Suppose their monthly expenditures are 5y and 7y, respectively.

Since each saves Rs 15,000 per month, 

Monthly saving of Aryan : $3 x-5 y=15,000$

Monthly saving of Babban : $4 x-7 y=15,000$

The above system of equations can be written in the matrix form as follows:

$\left[\begin{array}{ll}3 & -5 \\ 4 & -7\end{array}\right]\left[\begin{array}{l}x \\ y\end{array}\right]=\left[\begin{array}{l}15000 \\ 15000\end{array}\right]$

Now,

$|\mathrm{A}|=\left|\begin{array}{ll}3 & -5 \\ 4 & -7\end{array}\right|=-21-(-20)=-1$

$\operatorname{Adj} A=\left[\begin{array}{cc}-7 & -4 \\ 5 & 3\end{array}\right]^{T}=\left[\begin{array}{ll}-7 & 5 \\ -4 & 3\end{array}\right]$

So, $A^{-1}=\frac{1}{|A|} a d j A=-1\left[\begin{array}{ll}-7 & 5 \\ -4 & 3\end{array}\right]=\left[\begin{array}{ll}7 & -5 \\ 4 & -3\end{array}\right]$

$\therefore \mathrm{X}=\mathrm{A}^{-1} \mathrm{~B}$

$\Rightarrow\left[\begin{array}{l}x \\ y\end{array}\right]=\left[\begin{array}{ll}7 & -5 \\ 4 & -3\end{array}\right]\left[\begin{array}{l}15000 \\ 15000\end{array}\right]$

$\Rightarrow\left[\begin{array}{l}x \\ y\end{array}\right]=\left[\begin{array}{c}105000-75000 \\ 60000-45000\end{array}\right]$

$\Rightarrow\left[\begin{array}{l}x \\ y\end{array}\right]=\left[\begin{array}{l}30000 \\ 15000\end{array}\right]$

$\Rightarrow x=30,000$ and $y=15,000$

Therefore,

Monthly income of Aryan $=3 \times$ Rs $30,000=$ Rs 90,000

Monthly income of Babban $=4 \times$ Rs $30,000=$ Rs $1,20,000$

From this problem, we are encouraged to understand the power of savings. We should save certain part of our monthly income for the future.