The nth term of a sequence is given by an


The nth term of a sequence is given by an = 2n2 + n + 1. Show that it is not an A.P.


We have:

$a_{n}=2 n^{2}+n+1$

$a_{1}=2 \times 1^{2}+1+1$

= 4

$a_{2}=2 \times 2^{2}+2+1$


$a_{3}=2 \times 3^{2}+3+1$




and $a_{3}-a_{2}=22-11$


Since, $a_{2}-a_{1} \neq a_{3}-a_{2}$

Hence, it is not an AP.

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