The number of molecules with energy greater than the threshold energy for

Question:

The number of molecules with energy greater than the threshold energy for a reaction increases five fold by a rise of temperature from $27^{\circ} \mathrm{C}$ to $42^{\circ} \mathrm{C}$. Its energy of activation in $\mathrm{J} / \mathrm{mol}$ is______________. (Take $\ln 5=1.6094$; $\mathrm{R}=8.314 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}$ )

Solution:

$(84297.48)$

$\because k=A \mathrm{e}^{-E_{a} / R T}$

$\ln \frac{k_{2}}{k_{1}}=\frac{E_{a}}{R}\left(\frac{1}{T_{1}}-\frac{1}{T_{2}}\right) \Rightarrow \ln 5=\frac{E_{a}}{R}\left(\frac{1}{300}-\frac{1}{315}\right)$

$\Rightarrow E_{a}=\frac{1.6094 \times 8.314 \times 300 \times 315}{15}=84297.48 \mathrm{~J} / \mathrm{mol}$

Leave a comment

Close
faculty

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now