Question:
The overall stability constant of the complex ion $\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}$ is $2.1 \times 10^{13}$. The overall dissociations constant is $\mathrm{y} \times 10^{-14}$. Then $\mathrm{y}$ is .(Nearest integer)
Solution:
Given $\mathrm{k}_{\mathrm{f}}=2.1 \times 10^{13}$
$\mathrm{K}_{\mathrm{d}}=\frac{1}{\mathrm{k}_{\mathrm{f}}}=4.7 \times 10^{-14}$
$\therefore y=4.7 \approx 5$
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