The perimeters of two similar triangles ABC and PQR are 32 cm and 24 cm respectively.

Question:

The perimeters of two similar triangles ABC and PQR are 32 cm and 24 cm respectively. If PQ = 12 cm. find AB.

 

Solution:

It is given that triangles ABC and PQR are similar.
Therefore,

$\frac{\text { Perimeter }(\triangle A B C)}{\text { Perimeter }(\triangle P Q R)}=\frac{A B}{P Q}$

$\Rightarrow \frac{32}{24}=\frac{A B}{12}$

$\Rightarrow A B=\frac{32 \times 12}{24}=16 \mathrm{~cm}$

Leave a comment

Close
faculty

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now