The point on x-axis which is equidistant from points A(−1, 0) and B(5, 0) is


The point on x-axis which is equidistant from points A(−1, 0) and B(5, 0) is     

(a) $(0,2)$

(b) $(2,0)$

(c) $(3,0)$

(d) $(0,3)$



Let P(x, 0) the point on x-axis, then

$A P=B P \Rightarrow A P^{2}=B P^{2}$


$\Rightarrow x^{2}+2 x+1=x^{2}-10 x+25$

$\Rightarrow 12 x=24 \Rightarrow x=2$

Thus, the required point is (2, 0).
Hence, the correct answer is option (b).

Leave a comment


Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now