The proposition


The proposition $p \rightarrow \sim(p \wedge \sim q)$ is equivalent to:

  1. (1) $q$

  2. (2) $(\sim p) \vee q$

  3. (3) $(\sim p) \wedge q$

  4. (4) $(\sim p) \vee(\sim q)$

Correct Option: , 2


$\therefore p \rightarrow \sim(p \wedge \sim q)$ is equivalent to $\sim p \vee q$

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