The radius of the second Bohr orbit, in terms of the Bohr radius,

Question:

The radius of the second Bohr orbit, in terms of the Bohr radius, $a_{0}$, in $\mathrm{Li}^{2+}$ is:

  1. $\frac{2 a_{0}}{3}$

  2. $\frac{4 a_{0}}{9}$

  3. $\frac{4 a_{0}}{3}$

  4. $\frac{2 a_{0}}{9}$


Correct Option: , 3

Solution:

$r=\frac{a_{0} n^{2}}{\mathrm{Z}}$

For $\mathrm{Li}^{2+}, r=\frac{a_{0}(2)^{2}}{3}=\frac{4 a_{0}}{3}$

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