Question:
The rate constant for a first order reaction is 60 s−1. How much time will it take to reduce the initial concentration of the reactant to its 1/16th value?
Solution:
It is known that,
$t=\frac{2.303}{k} \log \frac{[\mathrm{R}]_{0}}{[\mathrm{R}]}$
$=\frac{2.303}{60 \mathrm{~s}^{-1}} \log 16$
$=4.6 \times 10^{-2} \mathrm{~s}$ (approximately)
Hence, the required time is 4.6 × 10−2 s.
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.