The ratio of mass percent of C and H of an organic compound


The ratio of mass percent of $\mathrm{C}$ and $\mathrm{H}$ of an organic compound $\left(\mathrm{C}_{\mathrm{X}} \mathrm{H}_{\mathrm{Y}} \mathrm{O}_{\mathrm{Z}}\right)$ is $6: 1$. If one molecule of the above compound $\left(\mathrm{C}_{\mathrm{X}} \mathrm{H}_{\mathrm{Y}} \mathrm{O}_{\mathrm{Z}}\right)$ contains half as much oxygen as required to burn one molecule of compound $\mathrm{C}_{\mathrm{X}} \mathrm{H}_{\mathrm{Y}}$ completely to $\mathrm{CO}_{2}$ and $\mathrm{H}_{2} \mathrm{O}$. The empirical formula of compound $\mathrm{C}_{\mathrm{X}} \mathrm{H}_{\mathrm{Y}} \mathrm{O}_{\mathrm{Z}}$ is

  1. $\mathrm{C}_{2} \mathrm{H}_{4} \mathrm{O}$

  2. $\mathrm{C}_{3} \mathrm{H}_{4} \mathrm{O}_{2}$

  3. $\mathrm{C}_{2} \mathrm{H}_{4} \mathrm{O}_{3}$

  4. $\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}_{3}$

Correct Option:


Leave a comment


Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now