The reaction in which the hybridisation of the underlined atom is affected is :-

$\underline{\mathrm{NH}_{3}} \stackrel{\mathrm{H}^{*}}{\longrightarrow}$

$\underline{\mathrm{XeF}}_{4}+\mathrm{SbF}_{5} \rightarrow$

$\mathrm{H}_{2} \underline{\mathrm{S}} \mathrm{O}_{4}+\mathrm{NaCl} \stackrel{420 \mathrm{~K}}{\longrightarrow}$

$\mathrm{H}_{3} \mathrm{PO}_{2} \stackrel{\text { Dispropartionation }}{\longrightarrow}$