Question:
The reaction of $\mathrm{H}_{3} \mathrm{~N}_{3} \mathrm{~B}_{3} \mathrm{Cl}_{3}(\mathrm{~A})$ with $\mathrm{LiBH}_{4}$ in tetrahydrofuran gives inorganic benzene (B). Further, the reaction of $(\mathrm{A})$ with $(\mathrm{C})$ leads to $\mathrm{H}_{3} \mathrm{~N}_{3} \mathrm{~B}_{3}(\mathrm{Me})_{3}$. Compounds (B) and (C) respectively, are:
Correct Option: , 4
Solution:
