The roots of the equation


The roots of the equation $2 x^{2}-6 x+7=0$ are

(a) real, unequal and rational
(b) real, unequal and irrational
(c) real and equal
(d) imaginary


(d) imaginary

$\because D=\left(b^{2}-4 a c\right)$

$=(-6)^{2}-4 \times 2 \times 7$



Thus, the roots of the equation are imaginary.


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