The shortest distance between the lines

Question:

The shortest distance between the lines

$\frac{x-3}{3}=\frac{y-8}{-1}=\frac{z-3}{1}$ and

$\frac{x+3}{-3}=\frac{y+7}{2}=\frac{z-6}{4}$ is

1. $\frac{7}{2} \sqrt{30}$

2. $3 \sqrt{30}$

3. 3

4. $2 \sqrt{30}$

Correct Option: , 2

Solution:

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