The statement


The statement $(p \rightarrow(q \rightarrow p)) \rightarrow(p \rightarrow(p \vee q))$ is :

  1. (1) equivalent to $(p \wedge q) \vee(\sim q)$

  2. (2) a contradiction

  3. (3) equivalent to $(p \vee q) \wedge(\sim p)$

  4. (4) a tautology

Correct Option: , 4


The truth table of $(p \rightarrow(q \rightarrow p)) \rightarrow(p \rightarrow(p \vee q))$ is

Hence, the statement is tautology.

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