The surface area of a cuboid formed

False

Three cubes having side x are joined face-to-face, then the cuboid so formed has the same height and breadth as the cubes but its length will be

thrice that of the cubes.

Hence, the length, breadth and height of the cuboid so formed are 3x, x and x, respectively. Then, its surface area = 2 (lb + bh + hl)

= 2(3x x x + x x x + x x 3 x )=2(3x2 + x2 + 3x2)

= 2 x 7x2 = 14x2

Now, the surface area of the cube of side x = 6 (Side)2 = 6x2 Hence, the statement is false.