Question:
the switch $S_{1}$ is closed at time $t=0$ and the switch $S_{2}$ is kept open. At some later time $\left(\mathrm{t}_{0}\right)$, the switch $\mathrm{S}_{1}$ is opened and $\mathrm{S}_{2}$ is closed. the behaviour of the current I as a function of time ' $\mathrm{t}$ ' is given by:
(1)
(2)
(3)
(4)
Correct Option: , 2
Solution:
The current will grow for the time $t=0$ to
$\mathrm{t}=\mathrm{t}_{0}$ and after that decay of current takes place.