The table given below shows the ages of 75 teachers in a school.

Total number of teachers = 75

(i) Number of teachers who are 40 or more than 40 years old = 37 + 8 = 45

$\therefore \mathrm{P}($ Selected teacher is 40 or more than 40 years old $)=\frac{\text { Number of teachers who are } 40 \text { or more than } 40 \text { years old }}{\text { Total number of teachers }}=\frac{45}{75}=\frac{3}{5}$

(ii) Number of teachers of an age lying between 30 – 39 years (including both) = 27

∴ P(Selected teacher is of an age lying between 30 – 39 years (including both))

$=\frac{\text { Number of teachers of an age lying between } 30-39 \text { years (including both) }}{\text { Total number of teachers }}=\frac{27}{75}=\frac{9}{25}$

(iii) Number of teachers 18 years or more and 49 years or less = 3 + 27 + 37 = 67 

$\therefore P($ Selected teacher is 18 years or more and 49 years or less $)=\frac{\text { Number of teachers } 18 \text { years or more and } 49 \text { years or less }}{\text { Total number of teachers }}=\frac{67}{75}$

(iv) Number of teachers 18 years or more old = 3 + 27 + 37 + 8 = 75 

$\therefore \mathrm{P}($ Selected teacher is 18 years or more old $)=\frac{\text { Number of teachers } 18 \text { years or more old }}{\text { Total number of teachers }}=\frac{75}{75}=1$

(v) Number of teachers above 60 years of age = 0 

$\therefore \mathrm{P}($ Selected teacher is above 60 years of age $)=\frac{\text { Number of teachers above } 60 \text { years of age }}{\text { Total number of teachers }}=\frac{0}{75}=0$