The tangent and normal to the ellipse

$3 x^{2}+5 y^{2}=32$

$\left.\frac{\mathrm{dy}}{\mathrm{dx}}\right|_{(2,2)}=-\frac{3}{5}$

Tangent : $\mathrm{y}-2=-\frac{3}{5}(\mathrm{x}-2) \Rightarrow \mathrm{Q}\left(\frac{16}{3}, 0\right)$

Normal : $\mathrm{y}-2=\frac{5}{3}(\mathrm{x}-2) \Rightarrow \mathrm{R}\left(\frac{4}{5}, 0\right)$

Area is $=\frac{1}{2}(\mathrm{QR}) \times 2=\mathrm{QR}=\frac{68}{15}$