Question:
The total number of isomers for a square planar complex $\left[\mathrm{M}(\mathrm{F})(\mathrm{Cl})(\mathrm{SCN})\left(\mathrm{NO}_{2}\right)\right]$ is :
Correct Option: 1
Solution:
The total number of isomers for a square planar complex $\left[\mathrm{M}(\mathrm{F})(\mathrm{Cl})(\mathrm{SCN})\left(\mathrm{NO}_{2}\right)\right]$ is 12 .
