The value of $K_{C}$ is 64 at $800 K$ for the reaction
$\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{~g})$
The value of $K_{C}$ for the following reaction is :
$\mathrm{NH}_{3}(\mathrm{~g}) \rightleftharpoons \frac{1}{2} \mathrm{~N}_{2}(\mathrm{~g})+\frac{3}{2} \mathrm{H}_{2}(\mathrm{~g})$
Correct Option: , 2
$\mathrm{N}_{2}+3 \mathrm{H}_{2} \rightleftharpoons 2 \mathrm{NH}_{3} \rightarrow \mathrm{K}_{\mathrm{C}}=64$
$2 \mathrm{NH}_{3} \rightleftharpoons \mathrm{N}_{2}+3 \mathrm{H}_{2} \rightarrow \mathrm{K}_{\mathrm{C}}=\frac{1}{64}$
$\mathrm{NH}_{3} \rightleftharpoons \frac{1}{2} \mathrm{~N}_{2}+\frac{3}{2} \mathrm{H}_{2} \rightarrow \mathrm{K}_{\mathrm{C}}=\left(\frac{1}{64}\right)^{1 / 2}=\frac{1}{8}$