# The width of each of the five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10.

Question:

The width of each of the five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. The upper class limit of the highest class is
(a) 45
(b) 25
(c) 35
(d) 40

Solution:

(c) 35

We have:
Class width = 5
Lower class limit of the lowest class = 10
Now,

Upper class limit of the highest class $=10+5 \times 5=35$