There is a circular tube in

Question:

There is a circular tube in a vertical plane. Two liquids which do not mix and of densities $d_{1}$ and $\mathrm{d}_{2}$ are filled in the tube. Each liquid subtends $90^{\circ}$ angle at centre. Radius joining their interface makes an angle $\alpha$ with vertical. Ratio $\frac{d_{1}}{d_{2}}$ is :

  1. $\frac{1+\tan \alpha}{1-\tan \alpha}$

  2. $\frac{1+\sin \alpha}{1-\cos \alpha}$

  3. $\frac{1+\sin \alpha}{1-\sin \alpha}$

  4. $\frac{1+\cos \alpha}{1-\cos \alpha}$


Correct Option: 1

Solution:

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