# There is a circular tube in

Question:

There is a circular tube in a vertical plane. Two liquids which do not mix and of densities $d_{1}$ and $\mathrm{d}_{2}$ are filled in the tube. Each liquid subtends $90^{\circ}$ angle at centre. Radius joining their interface makes an angle $\alpha$ with vertical. Ratio $\frac{d_{1}}{d_{2}}$ is :

1. $\frac{1+\tan \alpha}{1-\tan \alpha}$

2. $\frac{1+\sin \alpha}{1-\cos \alpha}$

3. $\frac{1+\sin \alpha}{1-\sin \alpha}$

4. $\frac{1+\cos \alpha}{1-\cos \alpha}$

Correct Option: 1

Solution: