Three coins are tossed simultaneously.

Question:

Three coins are tossed simultaneously. What is the probability of getting exactly two heads?

(i) $\frac{1}{2}$

(ii) $\frac{1}{4}$

(iii) $\frac{3}{8}$

 

(iv) $\frac{3}{4}$

 

Solution:

(C) $\frac{3}{8}$

Explanation:
When 3 coins are tossed simultaneously, the possible outcomes are HHH, HHT, HTH, THH, THT, HTT, TTH and TTT.
Total number of possible outcomes = 8

 Let E be the event of getting exactly two heads.

 Then, the favourable outcomes are  HHT, THH, and HTH.
 Number of favourable outcomes = 3

$\therefore$ Probability of getting exactly 2 heads $=P(E)=\frac{\text { Number of favo u rable outcomes }}{\text { Total number of possible outcomes }}=\frac{3}{8}$

 

 

 

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