Question:
Tick (✓) the correct answer:
The dimensions of a room are (10 m × 8 m × 3.3 m). How many men can be accommodated in this room if each man requires 3 m3 of space?
(a) 99
(b) 88
(c) 77
(d) 75
Solution:
(b) 88
Volume of the room $=10 \times 8 \times 3.3=264 \mathrm{~m}^{3}$
One person requires $3 \mathrm{~m}^{3}$.
$\therefore$ Total no. of people that can be accommodated $=\frac{264}{3}=88$
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