Two coins are tossed simultaneously 600 times to get 2 heads : 234 times, 1 head : 206 times, 0 head : 160 times.
Question:
Two coins are tossed simultaneously 600 times to get 2 heads : 234 times, 1 head : 206 times, 0 head : 160 times.
If two coins are tossed at random, what is the probability of getting at least one head?
(a) $\frac{103}{300}$
(b) $\frac{39}{100}$
(C) $\frac{11}{15}$
(d) $\frac{4}{15}$
Solution:
Number of times two coins are tossed simultaneously = 600
Number of times of getting at least one head = Number of times of getting 1 head + Number of times of getting 2 heads = 206 + 234 = 440
$\therefore \mathrm{P}($ Getting at least one head $)=\frac{\text { Number of times of getting at least one head }}{\text { Number of times two coins are tossed simultaneously }}=\frac{440}{600}=\frac{11}{15}$
Hence, the correct answer is option (c).