Two squares have sides x cm and (x + 4) cm.


Two squares have sides $x \mathrm{~cm}$ and $(x+4) \mathrm{cm}$. The sum of their areas is $656 \mathrm{~cm}^{2}$. Find the sides of the squares.


Given that the sides of two square be $x \mathrm{~cm}$ and $(x+4) \mathrm{cm}$

Then according to question


$x^{2}+x^{2}+8 x+16=656$

$2 x^{2}+8 x+16-656=0$

$2 x^{2}+8 x-640=0$

$x^{2}+4 x-320=0$

$x^{2}+20 x-16 x-320=0$








Since, sides of the squares being a positive, so x cannot be negative.


When $x=16$ then



Thus, sides of the squares be $16 \mathrm{~cm}, 20 \mathrm{~cm}$

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