# Use R=8.3 J/mol-K wherever required. The average translational kinetic energy of

Question:

Use $\mathrm{R}=8.3 \mathrm{~J} / \mathrm{mol}-\mathrm{K}$ wherever required.

The average translational kinetic energy of air molecules is $0.040 \mathrm{eV}\left(1 \mathrm{eV}=1.1 \times 10^{-19} \mathrm{~J}\right)$. Calculate the temperature of the air. Boltzmann constant $\mathrm{k}=1.38 \times 10^{-23} \mathrm{~J} / \mathrm{K}$.

Solution: