Question:
Using the formula (a + b)2 = (a2 + 2ab + b2), evaluate:
(i) (310)2
(ii) (508)2
(iii) (630)2
Solution:
(i) $310^{2}=(300+10)^{2}=\left(300^{2}+2(300 \times 10)+10^{2}\right)=90000+6000+100=96100$
(ii) $508^{2}=(500+8)^{2}=\left(500^{2}+2(500 \times 8)+8^{2}\right)=250000+8000+64=258064$
(iii) $630^{2}=(600+30)^{2}=\left(600^{2}+2(600 \times 30)+30^{2}\right)=360000+36000+900=396900$
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