Very-Short-Answer Questions


Very-Short-Answer Questions

Show that $x=-2$ is a solution of $3 x^{2}+13 x+14=0$.



The given equation is $3 x^{2}+13 x+14=0$.

Putting x = −2 in the given equation, we get

$\mathrm{LHS}=3 \times(-2)^{2}+13 \times(-2)+14=12-26+14=0=\mathrm{RHS}$

∴ x = −2 is a solution of the given equation.

Leave a comment


Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now