# Water in a canal 1.5 m wide and 6 m deep

Question:

Water in a canal 1.5 m wide and 6 m deep is flowing with a speed of 10km/hr. How much area will it irrigate in 30 minutes if 8 cm of standing water is desired?

Solution:

The canal is 1.5 m wide and 6 m deep. The water is flowing in the canal at 10 km/hr. Hence, in 30 minutes, the length of the flowing standing water is

$=10 \times \frac{30}{60} \mathrm{~km}$

$=5 \mathrm{~km}$

$=5000 \mathrm{~m}$

Therefore, the volume of the flowing water in 30 min is

$V_{1}=5000 \times 1.5 \times 6 \mathrm{~m}^{3}$

Thus, the irrigated area in 30 min of 8 cm=0.08 m standing water is

$=\frac{5000 \times 1.5 \times 6}{0.08}$

$=562500 \mathrm{~m}^{2}$