What can the maximum number of digits be in the repeating block of digits in the decimal expansion of $\frac{1}{17}$ ? Perform the division to check your answer.

Solution:

It can be observed that,

$\frac{1}{17}=0 . \overline{0588235294117647}$

There are 16 digits in the repeating block of the decimal expansion of $\frac{1}{17}$.