Question:
What is the length (in terms of π) of the arc that subtends an angle of 36° at the centre of a circle of radius 5 cm?
Solution:
We have
$r=5 \mathrm{~cm}$
$\theta=36^{\circ}$
We have to find the length of the arc.
Length of the $\operatorname{arc}=\frac{\theta}{360} \times 2 \pi r$
Substituting the values we get,
Length of the $\operatorname{arc}=\frac{36}{360} \times 2 \pi \times 5$.....(1)
Now we will simplify the equation (1) as below,
Length of the $\operatorname{arc}=\frac{1}{10} \times 2 \pi \times 5$
Length of the $\operatorname{arc}=\frac{1}{2} \times 2 \pi$
Length of the $\operatorname{arc}=\pi$
Therefore, length of the arc is $\pi \mathrm{cm}$