Question:
When a person leaves his home for sightseeing by his car, the meter reads 12352 km. When he returns home after two hours the reading is 12416 km.
(a) What is the average speed of the car during the period?
(b) What is the average velocity?
Solution:
(a) $\mathrm{V}_{\mathrm{avg}}=\frac{\text { Total distance }}{\text { time }}=\frac{(12416-12352)}{2}$
$V_{\text {avq }}=32 \mathrm{kmph}$
(b) $\vec{V}$ =displacement $/$ time
$\vec{V}_{\text {avg }}=0$
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